![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png){kind=small}
A little bit of busty science
Jul. 1st, 2004 07:05 pmA rather Brittish looking image doing math on bust implant sizes and extentions had a few intresting points... but had problems with the mathematics and the example. So lets refine it.
Lets assume each breast is like a beachball, so that the volume is basically 4/3¶r³. However, breasts are not like that! There's no way to attach them! So let's replace a part of the beach ball with a part of a cylendar. Only 1/8th of the beachball would need to be replaced to provide the right support, and be more accurate in terms of shape. We're allowing the bust, of course, to grow beyond the chest area.
So it's 7/8*4/3¶r³ + 1/4¶r³ (a quarter of a cylendar of r height and r radius). Simplify that a bit, and you get 17/12*¶r³.
6000 cc's, or cubic centimeters, is about 6 Liters of fluid. Some calculation results in r being a little more than 11 cm. Double that for the diameter, or in our case, how far would the bust pushes out from chest to nipple. A little over 22 cm, or 8.7 inches.
The cup size is measured from the largest part of the bust arround the body and back. It's circular in nature, but hey, we're going for more accuracy. A simple circle's not going to cut it. But we can optimze it. Since the measurement is in two sides that are roughly the same, we can just measure one and double it. So we're just doing from mid-chest to mid-back, and assume a roughly circular body, making the measurement much simpler. For sake of argument (based off of my RL body) I'll assume the r for the body is 8 inches (20.32 cm), and we'll call this b.
Roughly, the tape would travel linearly from the middle of the centerpoint, around 3/8ths of the circumfrence, travels linearly again, and then 1/8th of the circumfrence around the body to the center of the back. That latter linear measurement we'll have to calculate using the Pythagorian theorum, since it's two different radiuses, but attached at one point and then "moved" out to where the tape is. This makes the equasion 2*(r+3/4¶r+1/4¶b+sqrt(r^2+b^2)) (sqrt being a function for the square root of a value). Not eazily simplified, alas, but we have the values, we can plug it in.
The bust measurement is now roughly 152 cm, or 60 inches. My chest is roughly 48 inches, which means a difference of 12. Using the Pixelust/RW theorum, that's a FF cup bust!
Isn't Physics fun!
Lets assume each breast is like a beachball, so that the volume is basically 4/3¶r³. However, breasts are not like that! There's no way to attach them! So let's replace a part of the beach ball with a part of a cylendar. Only 1/8th of the beachball would need to be replaced to provide the right support, and be more accurate in terms of shape. We're allowing the bust, of course, to grow beyond the chest area.
So it's 7/8*4/3¶r³ + 1/4¶r³ (a quarter of a cylendar of r height and r radius). Simplify that a bit, and you get 17/12*¶r³.
6000 cc's, or cubic centimeters, is about 6 Liters of fluid. Some calculation results in r being a little more than 11 cm. Double that for the diameter, or in our case, how far would the bust pushes out from chest to nipple. A little over 22 cm, or 8.7 inches.
The cup size is measured from the largest part of the bust arround the body and back. It's circular in nature, but hey, we're going for more accuracy. A simple circle's not going to cut it. But we can optimze it. Since the measurement is in two sides that are roughly the same, we can just measure one and double it. So we're just doing from mid-chest to mid-back, and assume a roughly circular body, making the measurement much simpler. For sake of argument (based off of my RL body) I'll assume the r for the body is 8 inches (20.32 cm), and we'll call this b.
Roughly, the tape would travel linearly from the middle of the centerpoint, around 3/8ths of the circumfrence, travels linearly again, and then 1/8th of the circumfrence around the body to the center of the back. That latter linear measurement we'll have to calculate using the Pythagorian theorum, since it's two different radiuses, but attached at one point and then "moved" out to where the tape is. This makes the equasion 2*(r+3/4¶r+1/4¶b+sqrt(r^2+b^2)) (sqrt being a function for the square root of a value). Not eazily simplified, alas, but we have the values, we can plug it in.
The bust measurement is now roughly 152 cm, or 60 inches. My chest is roughly 48 inches, which means a difference of 12. Using the Pixelust/RW theorum, that's a FF cup bust!
Isn't Physics fun!
